Q. 1 A4.3( 7 Votes )

# The general form A. (4×100) + (5×10) + (6×1)

B. (4×100) + (6×10) + (5×1)

C. (5×100) + (4×10) + (6×1)

D. (6×100) + (5×10) + (4×1)

Answer :

For Option A,

The general or generalised form of a number is represented by base 10 of the given number.

We have been given the number, 456.

456 can be split as,

456 = 400 + 50 + 6

Or can be represented by base 10,

456 = (4 × 100) + (5 × 10) + (6 × 10^{0})

⇒ 456 = (4 × 100) + (5 × 10) + (6 × 1)

[∵ 400 = 4 × 100,

50 = 5 × 10,

6 = 6 × 1]

For Option B,

Solve: (4 × 100) + (6 × 10) + (5 × 1).

We get

(4 × 100) + (6 × 10) + (5 × 1) = 400 + 60 + 5

⇒ (4 × 100) + (6 × 10) + (5 × 1) = 465 ≠ 456

For Option C,

We need to solve (5 × 100) + (4 × 10) + (6 × 1).

(5 × 100) + (4 × 10) + (6 × 1) = 500 + 40 + 6

⇒ (5 × 100) + (4 × 10) + (6 × 1) = 546 ≠ 456

For Option D,

We need to solve (6 × 100) + (5 × 10) + (4 × 1).

(6 × 100) + (5 × 10) + (4 × 1) = 600 + 50 + 4

⇒ (6 × 100) + (5 × 10) + (4 × 1) = 654 ≠ 456

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