Q. 1 A4.0( 20 Votes )

Solve any five su

Answer :

Extend the segment RK to line l and draw perpendicular from point T to the line l at M as shown in the figure


TM becomes height of ∆TRP and ∆TPK



Area of triangle = (1/2) × base × height


A(∆TRP) = (1/2) × RP × TM


A(∆TPK) = (1/2) × PK × TM



using (i)



Hence A(∆TRP): A(∆TPK) = 3:2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USMaharashtra Board - Geometry Papers

Solve any five suMaharashtra Board - Geometry Papers

In <span lang="ENMHB - Mathematics Part-2

Some questions anMHB - Mathematics Part-2

Some questions anMHB - Mathematics Part-2

Some questions anMHB - Mathematics Part-2

Some questions anMHB - Mathematics Part-2

Solve the followiMHB - Mathematics Part-2

Solve the followiMHB - Mathematics Part-2

Solve the followiMHB - Mathematics Part-2