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Formula used.

(a + b)² = a² + b² + 2ab

(a + b)³ = a³ + b³ + 3ab(a + b)

Let a = m and b =

(a + b)² = a² + b² + 2ab

(m + )² = m² + ² + 2 × m ×

(√3)² = m² + + 2 × 1

3 = m² + + 2

m² + = 3 – 2 = 1

(a + b)³ = a³ + b³ + 3ab(a + b)

(m + )³ = m³ + ³ + 2 × m × × (m + )

(√3)³ = m³ + + 2 × 1 × (√3)

3√3 = m³ + + 2√3

m³ + = 3√3 – 2√3 = √3[3 – 2]

= √ 3