Q. 1 A4.0( 28 Votes )

# Expand(k + 4)3

(k + 4)3 =(k)3 + [ 3 ×(k)2 ×(4)] + [ 3 ×(k)×(4)2 ] +(4)3

{ (a + b)3 = a3 + 3a2b + 3ab2 + b3

Here a = k, b = 4 }

= k3 +(3 × 4)k2 +(3 × 16)k + 64

= k3 + 12k2 + 48k + 64

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