Answer :

(k + 4)^{3} =(k)^{3} + [ 3 ×(k)^{2} ×(4)] + [ 3 ×(k)×(4)^{2} ] +(4)^{3}

{ ∵(a + b)^{3} = a^{3} + 3a^{2}b + 3ab^{2} + b^{3}

Here a = k, b = 4 }

= k^{3} +(3 × 4)k^{2} +(3 × 16)k + 64

= k^{3} + 12k^{2} + 48k + 64

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