Q. 19 A5.0( 3 Votes )

In Figure 6, O is

Answer :

Given,


AC = 24 cm


AB = 7 cm


BOD = 90°


In right triangle BAC,


BAC = 90° [Angle in a semi-circle]


By Pythagoras’ theorem,


BC2 = AC2 + AB2


BC2 = 242 + 72


BC2 = 576 + 49 = 625


BC = √625 = 25 cm


Radius = OB = BC/2 = 25/2 = 12.5 cm


Area of the shaded region = Area of the circle – [area of ∆BAC + area of the quadrant]


=


= 490.625 – [84 + 122.656]


= 490.625 – 206.656


= 283.969 = 284 cm2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Glimpses of IndiaGlimpses of IndiaGlimpses of India39 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

The cost of fenciRS Aggarwal - Mathematics