Answer :

Let the increase in level of water in cylindrical tank be ‘h’ cm.

__Given__

Diameter of circular pipe = 2 cm

⇒ Radius of circular pipe, r_{1} = 1 cm [∵ diameter = 2 × radius]

Rate of flow = 0.7 m/sec

Height of Water flowed in half hour(1800 seconds) = 1800 × 0.7

= 1260 m = 126000 cm

Base radius of cylindrical tank, r_{2} = 40 cm

__Formula__

Volume of circular cylinder = πr^{2}h

Where, r is base radius and h is the height of cylinder

Now,

Water flowed from pipe in half hour = Volume of cylindrical tank with height h

⇒ Volume of pipe with height 126000 cm = Volume of cylindrical tank with height h

⇒ πr_{1}^{2}(126000) = πr_{2}^{2}h

⇒ 126000 = (40)^{2}h

⇒ 16h = 1260

⇒ h = 78.75 cm

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