Q. 194.1( 7 Votes )

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Answer :

Let the increase in level of water in cylindrical tank be ‘h’ cm.


Given


Diameter of circular pipe = 2 cm


Radius of circular pipe, r1 = 1 cm [ diameter = 2 × radius]


Rate of flow = 0.7 m/sec


Height of Water flowed in half hour(1800 seconds) = 1800 × 0.7


= 1260 m = 126000 cm


Base radius of cylindrical tank, r2 = 40 cm


Formula


Volume of circular cylinder = πr2h


Where, r is base radius and h is the height of cylinder


Now,


Water flowed from pipe in half hour = Volume of cylindrical tank with height h


Volume of pipe with height 126000 cm = Volume of cylindrical tank with height h


πr12(126000) = πr22h


126000 = (40)2h


16h = 1260


h = 78.75 cm


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