Q. 193.7( 6 Votes )

Two points A and B a

Answer :

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Given, height of the tower, PQ = 15 m


Angle of depression of A from top of tower = PAQ = 60°


Angle of depression of B from top of tower = PBQ = 45°


Let AQ = x m and BQ = y m


Consider ΔAPQ,


tan60° = PQ/AQ


√3 = 15/x


x = 5√3 m = 8.66 m


Consider ΔPBQ,


tan45° = PQ/BQ


1 = 15/y


y = 15 m


Distance between two points A and B = y – x = 15 – 5√3 m = 15 – 8.66 = 6.34 m


Ans. The distance between two points is 6.34 m.

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