# Two points A and B a

Given, height of the tower, PQ = 15 m

Angle of depression of A from top of tower = PAQ = 60°

Angle of depression of B from top of tower = PBQ = 45°

Let AQ = x m and BQ = y m

Consider ΔAPQ,

tan60° = PQ/AQ

√3 = 15/x

x = 5√3 m = 8.66 m

Consider ΔPBQ,

tan45° = PQ/BQ

1 = 15/y

y = 15 m

Distance between two points A and B = y – x = 15 – 5√3 m = 15 – 8.66 = 6.34 m

Ans. The distance between two points is 6.34 m.

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