Q. 19

The radius

Answer :

Let r be the radius of sphere and V be the volume


Let r1 = 10 cm and r2 = 9.8 cm


The change dr is given by dr = r2 – r1


dr = 9.8 – 10 = -0.2 cm …(i)


Now volume of sphere is given by



As we have to find the change in V (that is dV) with respect to r, we have to differentiate V with respect to r




dV = 4πr2dr


The radius is shrinked from 10 cm hence r will be 10 and put dr value from (i)


dV = 4π(10)2(-0.2)


dV = -4π(20)


dV = -80π


The negative sign indicates that the volume is decreased


Hence the change in volume or decrease in volume is 80π cm3


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

If y = sin x and RD Sharma - Volume 1

Find the percentaRD Sharma - Volume 1

A circular metal RD Sharma - Volume 1

The radius of a sRD Sharma - Volume 1

The height of a cRD Sharma - Volume 1

Find the approximMathematics - Exemplar

Find the point onMathematics - Board Papers