Q. 194.0( 4 Votes )

# The lengths of th

Answer :

Given, Length of the height of the right- triangle = 12cm

Length of base = 5cm

According to the Pythagoras theorem

⇒ AC^{2} + CB ^{2} = AB^{2}

⇒ 12^{2} + 5^{2} = AB^{2}

⇒ 144 + 25 = AB^{2}

⇒ AB = √ 169

⇒ AB = 13 cm

Now, Area of triangle ABC = ……. Eq 1

⇒ Area of right Triangle ABC =

⇒ Area of right-angle triangle = 30 cm^{2}

Now according to given condition CD is perpendicular to AB

⇒ Area of triangle ABC = AB × h (from eq 1)

⇒

⇒

⇒ h = 4.62cm

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