# The angles of dep

From the condition given in the question the figure can be drawn as follows:

Let us assume AE be the building and CD be the tower

Let the height of the tower be h m

And horizontal distance between tower and building be x m

It is given in the question that,

BD = AE = 50 m

BC = CD – BD

= (h – 50) m

Now in right triangle ABC, we have:

x = h – 50 (i)

Also, in right triangle CDE, we have

Now putting the value of x from (i) we get:

= 25 × 4.73

= 118.25

Now, putting the value of h in (i) we get:

x = h – 50

= 118.25 – 50

= 68.25 m

Hence, height of the tower is 118.25 m and the horizontal distance between tower and building is 68.25 m

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