# Solve the followi

Given:

Dividing both sides by cos2 x, we get

… (1)

Which is a linear differential equation of the form

Here P=sec2 x, Q = tan x. sec2 x

Solution is

Putting tan x = t sec2 x dx = dt

yet = tet – et + c = et (t – 1) + c

Since tan x = t,

y = tan x – 1 + ce-tan x

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