Q. 195.0( 3 Votes )

# Prove that the po

Answer :

Let the A(3, 0), B(6, 4) and C(- 1, 3) are three vertices.

Now using distance formula for two points A(x1, y1) and B(x2, y2) We have  = 5 units    = 5 units

Now, AB > BC = AC

Therefore, if ABC is a right angled triangle. AB should be hypotenuse. BC and AC should be other two sides.(i.e. perpendicular and base)

And should satisfy the Pythagoras theorem, that says

(hypotenuse)2 = (perpendicular)2 + (base)2

AB2 = BC2 + AC2

Taking RHS  = LHS

Hence ABC is a right angled triangle.

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