Prove that the po

Let the A(3, 0), B(6, 4) and C(- 1, 3) are three vertices.

Now using distance formula for two points A(x₁, y₁) and B(x₂, y₂)

We have

= 5 units

= 5 units

Now, AB > BC = AC

Therefore, if ABC is a right angled triangle. AB should be hypotenuse. BC and AC should be other two sides.(i.e. perpendicular and base)

And should satisfy the Pythagoras theorem, that says

(hypotenuse)² = (perpendicular)² + (base)²

AB² = BC² + AC²

Taking RHS

= LHS

Hence ABC is a right angled triangle.