Q. 195.0( 3 Votes )

# In the given figure AB || CD. If ∠OAB = 124°, ∠OCD = 136°, then ∠AOC = ?

A. 80°

B. 90°

C. 100°

D. 110°

Answer :

Draw a line EF such that EF || AB and EF || CD crossing point O.

FOC + OCD = 180^{o} (Sum of consecutive interior angles is 180^{o})

FOC = 180 – 136 = 44^{o}

EF || AB such that AO is traversal.

OAB + FOA = 180^{o}(Sum of consecutive interior angles is 180^{o})

FOA = 180 – 124 = 56^{o}

AOC = FOC + FOA

= 56 + 44

=100^{o}

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In the given figure, AB || CD. If ∠ABO = 130° and ∠OCD = 110°, then ∠BOC = ?

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