# In the given figure AB || CD. If ∠OAB = 124°, ∠OCD = 136°, then ∠AOC = ?A. 80°B. 90°C. 100°D. 110°

Draw a line EF such that EF || AB and EF || CD crossing point O.

FOC + OCD = 180o (Sum of consecutive interior angles is 180o)

FOC = 180 – 136 = 44o

EF || AB such that AO is traversal.

OAB + FOA = 180o(Sum of consecutive interior angles is 180o)

FOA = 180 – 124 = 56o

AOC = FOC + FOA

= 56 + 44

=100o

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