Answer :

Draw a line EF such that EF || AB and EF || CD crossing point O.


FOC + OCD = 180o (Sum of consecutive interior angles is 180o)


FOC = 180 – 136 = 44o


EF || AB such that AO is traversal.


OAB + FOA = 180o(Sum of consecutive interior angles is 180o)


FOA = 180 – 124 = 56o


AOC = FOC + FOA


= 56 + 44


=100o

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