Q. 194.5( 11 Votes )

In Fig. 5, from a

Answer :

Total Surface area of cuboide (before drilling) = 2(lb + bh + lh)

T.S.A. cuboid = 2(15 × 10 + 10 × 5 + 15 × 5) = 2(275) = 550cm2


Radius of cylindrical hole = 7/2 = 3.5cm




Surface Area of remaining block = (Total surface Area of cuboid)


-(Area of two circular bases)


+ (Curved surface area of cylinder)


Surface area of remaining block = 550-77 + 110 = 583cm2


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