Q. 195.0( 1 Vote )
Mark the tick aga A. (a – b) (b – c) (c – a)
B. -(a – b) (b – c) (c – a)
C. (a + b) (b + c) (c + a)
D. None of these
Answer :
To find: Value of 
We have, 
Applying 
⇒ 
⇒ 
Taking (b – a) common
⇒ 
Applying 
⇒ 
⇒ 
Taking (c - b) common
⇒ 
Expanding along C3
⇒ (b – a) (c – b) [1{(c) (1) – (a) (1)}]
⇒ (b – a) (c – b) (c – a)
⇒ (a – b) (b – c) (c – a)
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