Q. 195.0( 1 Vote )

Mark the tick aga A. (a – b) (b – c) (c – a)


B. -(a – b) (b – c) (c – a)

C. (a + b) (b + c) (c + a)

D. None of these

Answer :

To find: Value of


We have,


Applying




Taking (b – a) common



Applying




Taking (c - b) common



Expanding along C3


(b – a) (c – b) [1{(c) (1) – (a) (1)}]


(b – a) (c – b) (c – a)


(a – b) (b – c) (c – a)

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