Answer :

Construction:


The situation looks like this –



At the intersection points, x = 2y = y2


or, y2 – 2y = 0


y(y – 2) = 0


y = 0 or y = 2


So, intersection points are (0, 0) and (4, 2)


Hence, the area A enclosed is –


A =


=


= [4 – 8/3]


= 4/3 (Ans)

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