Answer :
given: bag which contains 8 red and 5 white balls
We know,
total number of ways of drawing three balls at random is 13C3.
therefore n(S)=286
(i) let E be the event of getting all white balls
E= {(W) (W) (W)}
n(E)= 5C3
=10
(ii) let E be the event of getting all red balls
E= {(R) (R) (R)}
n(E)= 8C3
=56
(iii) let E be the event of getting one red and two white balls
n(E)= 8C1× 5C2
=80
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