Q. 18 E

In parallelogram ABCD, AB = 4 cm., BC = 6 cm. and ABC = 30°, find the area of field in the shape of parallelogram ABCD.

Answer :

Consider a parallelogram ABCD, such that AB = 4 cm, BC = 6 cm and ABC = 30°, Draw AE BC



We know, area of parallelogram = Base × Height


area(ABCD) = AE × BC


In ΔAEB


We know,





AE = 2 cm


Hence, area of ABCD = 2 × 6 = 12 cm2


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