Answer :

Given, Length of height of rhombus is 4 cm. and length of side is 5 cm.

Hence, DB= 4cm and then BO = 2cm

By Pythagoras theorem,

BO2 + AO2 = AB2

22 + AO2 = 52

AO2 = 25 – 4

AO =

AO = 4.6cm

Hence, AC = 2.AO

AC = 2×4.6

AC = 9.2 cm

Area of rhombus = ×4×9.2

= 18.4 sq. cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Area of field in West Bengal Mathematics

The base of a parWest Bengal Mathematics

If perimeter of aWest Bengal Mathematics

The area of fieldWest Bengal Mathematics

In a quadrilateraWest Bengal Mathematics

In parallelogram West Bengal Mathematics

The length of oneWest Bengal Mathematics

The length West Bengal Mathematics

If the lengWest Bengal Mathematics

The lengths of paWest Bengal Mathematics