Q. 185.0( 3 Votes )

Using properties

Answer :

To Prove:


Proof:



Applying R1 R1 + R3 and R2 R2 + R3



Now, taking (a + c) common from the first row and (b + c) common from the second row, we have,



Expanding, we get,


= (a + c)(b + c)[a + b + c + a + (- a – b – c + b) + 1(a + b)]


= (a + c)(b + c)[2a + 2b]


= 2(a + b)(b + c)(c + a)


= R.H.S


Hence, Proved.


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