Sum of first n terms of an AP is given by-Sn = 3n2+4n∴ S25 = 3(25)2+4(25) = 3×625+100 = 1975and,S24 = 3(24)2+4(24) = 3×576+96 = 1824Thus, 25th term of AP = S25- S24 = 1975 - 1824 =151

Q. 185.0( 4 Votes )

The sum of first

Class 10th Mathematics - Board Papers CBSE - 2013

Answer :

Sum of first n terms of an AP is given by-

S_n = 3n²+4n

∴ S₂₅ = 3(25)²+4(25) = 3×625+100 = 1975

and,S₂₄ = 3(24)²+4(24) = 3×576+96 = 1824

Thus, 25th term of AP = S₂₅- S₂₄ = 1975 - 1824 =151

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