Q. 18

Mark against the A. (-10, 10, 3)

B. (10, 10, -3)

C. (10, -10, 3)

D. (10, -10, -3)

Answer :

Given: Line meets plane 2x – y + 3z – 1 = 0


To find: Point of intersection of line and plane.


Explanation:


Let the equation of the line be



Therefore, any point on the line is (3λ + 1, 4λ - 2, -2λ + 3)


Since this point also lies on the plane,


2(3λ + 1) - (4λ -2) + 3(-2λ +3) = 1


6λ + 2 – 4λ + 2 – 6λ + 9 = 1


-4λ = -12


λ = 3


Therefore required point is (10, 10, -3)

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