Q. 184.5( 17 Votes )

# The digits of a p

Answer :

Let the three digits be (a - d), a and (a + d). Clearly these three are in AP

Then the no is = 100(a - d) + 10(a) + a + d = 100a - 100d + 10a + a + d = 111a - 99d

Also sum of digits = 15

(a - d) + a + (a + d) = 15

3a = 15

a = 5

Also,

When no is reversed no is = 100(a + d) + 10(a) + a - d = 111a + 99d

Given that

Original No - 594 = reversed No

111a - 99d - 594 = 111a + 99d

198d = - 594

d = - 3

So the original No is = 111a - 99d = 111(5) - 99( - 3) = 555 + 297 = 852

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