Q. 184.4( 20 Votes )

The angle of elevation of the top of a tower from a point on the ground 30 m away from the foot of the tower is 30°. The height of the tower is
A. 30 m

B. 10√3m

C. 20 m

D.10√2 m

Answer :


In the above figure, let AB be the tower and C be the point on the ground 30 m away from the foot of AB from where the point A is observed. Join B, C and A, C. We get a right-angled triangle ABC with right angle at B. BC = 30 m. Also, the angle of elevation of the top of the tower AB from C is 30°. So, ACB = 30°. We need to find the height of the tower, that is, AB.

In ∆ABC,



Hence the correct choice is B.

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