Q. 185.0( 14 Votes )

The angle of elev

Answer :

Let P and Q be the two positions of the aeroplane and A be the point of observation. Let ABC be the horizontal line through A. It is given that angles of elevation of the plane in two positions P and Q from a point A are 60° and 30° respectively.

PAB = 60° and QAB = 30°

Also given PB = 3000√3 m


tan 60° = BP/AP


AB = 3000 m


tan 30° = CQ/AC

AC = 3000 (3)

AC = 9000 m

Distance, BC = AC – AB = 9000 – 3000 = 6000 m

Thus, the plane travels 6000m in 30 seconds.

We know that speed = distance/time

Speed of plane = 200 m/sec

Speed of the aeroplane is 200 m/sec.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
All GrammarAll GrammarAll Grammar41 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses