Q. 184.1( 25 Votes )

Seg AM is a median of ∆ ABC. If AB = 22, AC = 34, BC = 24, find AM

Answer :


We know, By Apollonius theorem


In ΔABC, if M is the midpoint of side BC, then AB2 + AC2 = 2AM2 + 2BM 2


Given that,


AB = 22, AC = 34, BC = 24


AP is median i.e. P is the mid-point of BC



Putting values in equation


222 + 342 = 2AM2 + 2(12)2


484 + 1156 = 2AM2 + 288


1352 = 2AM2


AM2 = 676


AM = 26


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