Answer :

**To Find: Values of x and y**

**Given: PQ is perpendicular to PS, PQ parallel SR**

**∠****SQR = 28 ^{o}**

**And,** **∠****QRT = 65 ^{o}**

Now according to the question,

x + ∠SQR = ∠QRT (Alternate angles are equal as QR is transversal)

x + 28^{o} = 65^{o}

x = 37^{o}

Now, in Δ PQS, Sum of interior angles of a triangle = 180°

∠ PQS + ∠ PSQ + ∠ QPS = 180°

Therefore,

y + 37° + 90° = 180°

y = 53°

**So, x = 37° and y = 53°**

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