In Fig., if PQ <s

To Find: Values of x and y

Given: PQ is perpendicular to PS, PQ parallel SR

SQR = 28o

And, QRT = 65o

Now according to the question,

x + SQR = QRT (Alternate angles are equal as QR is transversal)

x + 28o = 65o

x = 37o

Now, in Δ PQS, Sum of interior angles of a triangle = 180°

PQS + PSQ + QPS = 180°

Therefore,

y + 37° + 90° = 180°

y = 53°

So, x = 37° and y = 53°

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