Q. 184.0( 4 Votes )

In Fig. 14.114, A

Answer :

Given,


ABCD is a rectangle


ECD = 146°


= ECD+DCO = 180° (Linear pair of angles)


=146°+DCO = 180°


= DCO = 180° - 146° = 34°


AND, BOC = 180°- OCB-OBC OCB = OBC


=BOC = 180°-34°-34° = 112°


BOC+AOB = 180° (Linear pair)


= 112°+ AOB = 180°


= AOB = 180°- 112° = 68°


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