Q. 185.0( 1 Vote )

Find the point on

Answer :

Given; y = x3 - 11x + 5 and the equation of tangent is y = x - 11


Slope of the tangent is the coefficient of x [y = mx + c] = 1



From the first equation;



From (i) and (ii)


3x2 − 11 = 1


3x2 = 12


x = ±2


y = x − 11 = −13, −9


The required points are (2,−9) and (−2,−13)


OR


Given; √49.5


Let f(x) = √x and f(x + δx) = √(x + δx)


Here; x = 49 and δx = 0.5


We know;



f(x + δx) = δx f(x) + f(x)


Here;





= 7.036


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

If y = sin x and RD Sharma - Volume 1

Find the percentaRD Sharma - Volume 1

A circular metal RD Sharma - Volume 1

The radius of a sRD Sharma - Volume 1

The height of a cRD Sharma - Volume 1

Find the approximMathematics - Exemplar

Find the point onMathematics - Board Papers