Q. 184.5( 2 Votes )

# Find the equation of the line parallel to y-axis and drawn through the point of intersection of the lines x – 7y + 5 = 0 and 3x + y = 0.

The equation of any line parallel to the y – axis is of the form

x = a -------- (1)

The two given lines are

x – 7y + 5 = 0 ---------(2)

3x + y = 0 ------- (3)

Multiply eq (2) with 3 and subtract eq(3) from it to get,

3x - 21y + 15 - 3x - y = 0

-22y = -15

Put value of y in eq(3) to get,

Thus,

is the point of intersection of lines (2) and (3).

Since, line x = a pass through point a =

Therefore, the required equation of the line is x =

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