# Find: <img

Using partial fraction method,

By cross–multiplying we get,

4 = A(x2 + 4) + (Bx + C)(x – 2)

4 = Ax2 + 4A + Bx2 – 2Bx + Cx–2C

4 = (A + B) x2 + (C–2B)x–2C + 4A

On equating, same coefficients we have,

A + B = 0, C–2B = 0 & 4A–2C = 0

On solving, we get

On integrating we get,

Hence,

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