Q. 18

Find a positive v

Answer :

The general term Tr+1 in the binomial expansion is given by Tr+1 = nCr an-r br

Here a = 1, b = x and n = m


Putting the value


Tr+1 = mCr 1m-r xr


= mCr xr


We need coefficient of x2


putting r = 2


T2+1 = mC2 x2


The coefficient of x2 = mC2


Given that coefficient of x2 = mC2 = 6




m(m-1) = 12


m2- m - 12 =0


m2- 4m +3m - 12 =0


m(m-4) + 3(m-4) = 0


(m+3)(m - 4)= 0


m = - 3, 4


we need positive value of m so m = 4

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Show that the coeRS Aggarwal - Mathematics

Show that the midRS Aggarwal - Mathematics

Show that the coeRS Aggarwal - Mathematics

Show that the terRS Aggarwal - Mathematics

Find the middle tRS Aggarwal - Mathematics

If the 17th<RS Aggarwal - Mathematics

If the coefficienRS Aggarwal - Mathematics

Prove that the coRS Aggarwal - Mathematics