Answer :

Given-

_{Diameter of Hemispherical bowl = 14 cm}

_{∴} _{Radius of Hemispherical Bowl(r) = Radius of Cylinder(r)}

_{= 7 cm}

_{Total Height of Vessel = 13 cm}

_{∴} _{Height of Cylinder(h) = 13-7 = 6 cm}

_{Curved Surface Area of Cylinder = 2× π × r× h}

_{= 2× (22/7) × 7× 6}

_{= 264 sq. cm}

_{Curved Surface Area of Hemispherical Bowl = 2 × π × (r)}^{2}

_{= 2× (22/7) × (7)}^{2}

_{= 308 sq. cm}

Thus, total (inner) surface area of the vessel = 264+308

= 572 sq. cm

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