Q. 175.0( 7 Votes )

In the given figu

Answer :

Given: ∆ ABC and ∆ DBC have the same base BC.

AD and BC intersect at O.

To show:

First, we construct the altitudes, AE and DF, of ∆ ABC and ∆ DBC, respectively.

Consider, ∆ AOE and ∆ DOF,

DFO = AEO [Right angles]

DOF = AOE [Vertically Opposite angles]

So, by AA criterion,


Ratio of all the corresponding sides of ∆ AOE and ∆ DOF are equal.


Now, we know that


Similarly, ……….(iii)

Dividing (ii) by (iii),

[From (i)]

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