Q. 174.0( 4 Votes )

In Fig. 9.43, if EC||AB, ECD =70° and BDO =20° , then OBD is


A. 20°

B. 50°

C. 60°

D. 70°

Answer :

Given,

EC AB


ECD = 70o


BDO = 20o


Since,


EC AB


And, OC cuts them so


ECD = 1 (Alternate angle)


1 = 70o


1 + 3 = 180o (Linear pair)


3 = 110o


In


BOD + OBD + BDO = 180o


3 + ODB + 20o = 180o


ODB = 50o

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