Q. 174.0( 4 Votes )

In Fig. 9.43, if EC||AB, ECD =70° and BDO =20° , then OBD is

A. 20°

B. 50°

C. 60°

D. 70°

Answer :



ECD = 70o

BDO = 20o



And, OC cuts them so

ECD = 1 (Alternate angle)

1 = 70o

1 + 3 = 180o (Linear pair)

3 = 110o


BOD + OBD + BDO = 180o

3 + ODB + 20o = 180o

ODB = 50o

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