# In Fig. 8.129, PQ++RS, ∠AEF =95°, ∠BHS =110° and ∠ABC =x°. Then the value of x is,A. 15°B. 25°C. 70°D. 35°

Given that,

PQ RS

AEF = 95o

BHS = 110o

ABC = xo

AEF = AGH = 95o (Corresponding angles)

AGH + HGB = 180o (Linear pair)

95o + HGB = 180o

HGB = 85o

BHS + BHG = 180o (Linear pair)

110o + BHG = 180o

BHG = 70o

In BHG,

BHG + HGB + GBH = 180o

70o + 95o + GBH = 180o

GBH = 25o

Thus,

ABC = GBH = 25o

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