Q. 174.9( 8 Votes )

# In Fig. 4, AB and

Answer :

Given-

AB and CD are the diameters of bigger circle with centre O and OA = 7 cm.

Radius of Bigger Circle(R) = 7 cm

Radius of Smaller Circle(r) = (7/2) cm

Area of Δ ADC = (1/2) × Base× Corresponding Altitude

= (1/2) × CD× OA

= (1/2) × 14× 7

= 49 sq. cm

Area of Semicircular Region CAD = (1/2) × Area of Bigger Circle

= (1/2) × π × (R)2

= (1/2) × (22/7) × (7)2

= 77 sq. cm

Area of Smaller circle = π × (r)2

= (22/7) × (7/2)2

= (77/2)

= 38.5 sq. cm

Thus, Area of Shaded Region

= Area of Smaller circle+ Area of Semicircular Region CAD- Area of ΔADC

= 38.5 + 77 - 49

= 66.5 sq. cm

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