Answer :

Given-

AB and CD are the diameters of bigger circle with centre O and OA = 7 cm.

∴ Radius of Bigger Circle(R) = 7 cm

_{Radius of Smaller Circle(r) = (7/2) cm}

_{Area of Δ ADC = (1/2) × Base× Corresponding Altitude}

_{= (1/2) × CD× OA}

_{= (1/2) × 14× 7}

_{= 49 sq. cm}

_{Area of Semicircular Region CAD = (1/2) × Area of Bigger Circle}

_{= (1/2) × π × (R)}^{2}

_{= (1/2) × (22/7) × (7)}^{2}

_{= 77 sq. cm}

_{Area of Smaller circle = π × (r)}^{2}

_{= (22/7) × (7/2)}^{2}

_{= (77/2)}

_{= 38.5 sq. cm}

_{Thus, Area of Shaded Region}

_{= Area of Smaller circle+ Area of Semicircular Region CAD- Area of ΔADC}

_{= 38.5 + 77 - 49}

_{= 66.5 sq. cm}

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