# If angles A, B, C of a ΔABC form an increasing AP, then sin B =A. 1/2B. √3/2C. 1D. 1/√2

Let suppose A, B and C are the angles of a triangle ABC, In ∆ABC,

A = (a – d)

B = a

C = a + d

Now, form an increasing A.P

As we know Sum of all the angle of a triangle is 180°,

Therefore,

A + B + C = 180°

(a – d) + a + (a + d) = 180°

3a = 180°

a = 180/3 = 60°

From the table,

sin B = sin A = sin 60°

= √3/2

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