Answer :
Given: A is a skew-symmetric matrix of order 3.
To Prove: det(A) = 0
Concept Used:
For a skew-symmetric matrix
AT = -A
Explanation:Taking determinant on both sides, we get-
|AT| = |-A|
⇒ |A| = (-1)3|A|
[∵ the value of determinant remains unchanged if its rows and columns are interchanged.]
[∵ |kA| = kn|A| where n is the order of matrix]
⇒ |A| = -|A|
⇒ 2|A| = 0
⇒ |A| = 0
Hence, If A is a skew-symmetric matrix of order 3, then |A| is zero.
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