Answer :
Given equation of the line 12(x + 6) = 5(y – 2).
⇒ 12x + 72 = 5y – 10
⇒12x – 5y + 82 = 0 … (1)
Comparing equation (1) with general equation of line Ax + By + C = 0, we obtain A = 12, B = –5, and C = 82
Perpendicular distance (d) of a line Ax + By + C = 0 from a point (x1, y1) is given by
Given point (x1, y1) = (-1, 1)
∴ distance of point (–1, 1) from the given line
d = 5 units
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