Answer :

Given:

and


So,









We know that



where θ is the angle between


According to the question our equation becomes,


…(i)


Now,



= (5.(-1)) + (0).(1) + (1).(5)


= -5 + 5


= 0


Magnitude of



Magnitude of



Now, putting the values in eq. (i), we get


0 = √26 √30 cos θ


cos θ = 0



So, the angle between


Now, we have to find the vector which is perpendicular to


A vector perpendicular to both





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