Answer :




We know that

where θ is the angle between

According to the question our equation becomes,



= (5.(-1)) + (0).(1) + (1).(5)

= -5 + 5

= 0

Magnitude of

Magnitude of

Now, putting the values in eq. (i), we get

0 = √26 √30 cos θ

cos θ = 0

So, the angle between

Now, we have to find the vector which is perpendicular to

A vector perpendicular to both

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