Answer :

We have,










= tan x – cot x - 3x +C


OR



Let


x-3 = A(2x+3) +B


x-3 = 2Ax+(3A+B)


Equating the coefficient, we get


2A=1 and 3A+B=-3






Let


And



Now,


Let x2+3x-18 = t


2x+3 dx=dt




Again,


=


=


=


Thus,




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