Q. 16 D4.0( 7 Votes )

# In the triangle A Given: BD = 8 cm

DC = 2 cm

By applying Pythagoras theorem to ΔACD we get,

AC2 = 42 + 22

AC2 = 16 + 4

AC2 = 20 ……………………… (1)

By applying Pythagoras theorem to ΔABD we get,

AB2 = 42 + 82

AB2 = 16 + 64

AB2 = 80 ……………………… (2)

Now,

BC = BD + DC

BC = 8 + 2

BC = 10

BC2 = 102 = 100 ……………… (3)

By adding eqns. (1) and (2) and equating with (3) we get,

BC2 = AB2 + AC2

h2 = p2 + b2

OR,

BAC is a right angle.

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