Q. 16 D4.0( 7 Votes )

# In the triangle A

Answer :

Given: BD = 8 cm

DC = 2 cm

AD = 4 cm

By applying Pythagoras theorem to ΔACD we get,

AC^{2} = AD^{2} + CD^{2}

AC^{2} = 4^{2} + 2^{2}

AC^{2} = 16 + 4

AC^{2} = 20 ……………………… (1)

By applying Pythagoras theorem to ΔABD we get,

AB^{2} = AD^{2} + BD^{2}

AB^{2} = 4^{2} + 8^{2}

AB^{2} = 16 + 64

AB^{2} = 80 ……………………… (2)

Now,

BC = BD + DC

BC = 8 + 2

BC = 10

BC^{2} = 10^{2} = 100 ……………… (3)

By adding eqns. (1) and (2) and equating with (3) we get,

BC^{2} = AB^{2} + AC^{2}

⇒ h^{2} = p^{2} + b^{2}

OR,

∠BAC is a right angle.

Rate this question :

A person goes 24mWest Bengal Board - Mathematics

Two rods of 13m. West Bengal Board - Mathematics

In ΔABC, if AB = West Bengal Board - Mathematics

If the lengths ofWest Bengal Board - Mathematics

In the adjoining West Bengal Board - Mathematics

I have drawn a trWest Bengal Board - Mathematics

Let us fill in blWest Bengal Board - Mathematics

In ΔRST, <span laWest Bengal Board - Mathematics

If the followingsWest Bengal Board - Mathematics

The point O is siWest Bengal Board - Mathematics