Answer :


Given: BD = 8 cm


DC = 2 cm


AD = 4 cm


By applying Pythagoras theorem to ΔACD we get,


AC2 = AD2 + CD2


AC2 = 42 + 22


AC2 = 16 + 4


AC2 = 20 ……………………… (1)


By applying Pythagoras theorem to ΔABD we get,


AB2 = AD2 + BD2


AB2 = 42 + 82


AB2 = 16 + 64


AB2 = 80 ……………………… (2)


Now,


BC = BD + DC


BC = 8 + 2


BC = 10


BC2 = 102 = 100 ……………… (3)


By adding eqns. (1) and (2) and equating with (3) we get,


BC2 = AB2 + AC2


h2 = p2 + b2


OR,


BAC is a right angle.


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