Answer :

Given: (x2 + 3xy + y2)dx – x2dy = 0



…(i)


Let y = vx


On differentiating, we get




Putting the value of in eq. (i), we get






Integrating both the sides, we get





Now, put back the value of



…(ii)


It is given that when x=1, y=0



-1 = C [ log (1) = 0]


Putting the value of C in eq. (ii), we get








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