Take ex out from the denominator.
Let, e-x + 2 = t
Differentiating both sides with respect to x
-dt = e-x dx
Y = -ln t + c
Again, put e-x + 2 = t
Y = -ln(e-x + 2) + c
Note: Don’t forget to replace t with the function of x at the end of solution. Always put constant c with indefinite integral.
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