Q. 165.0( 4 Votes )

# Three coins are tossed together. Find the probability of getting:

(i) exactly two heads

(ii) at most two heads

(iii) at least one head and one tail.

(iv) no tails

Answer :

**Concept Used:**

**Explanation:**

Sample space = {(H, H, H), (H, H, T), (H, T, T), (H, T, H), (T, H, H), (T, T, H), (T, H, T), (T, T, T)}

(i) P(Exactly two heads) =?

Now,

Total Possible outcomes = 8

Total favourable outcomes = 3

(ii) P(at most two heads) =?

At most two heads mean that the number of heads should be 2 or less than 2.

Total Possible outcomes = 8

Total favourable outcomes = 4

(iii) P(at least one head and at least one tail) =?

Total possible outcomes = 8

Total favourable outcomes = 6

(iv) P(no tails) = ?

Total possible outcomes = 8

Total favourable outcomes = 1

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