Q. 164.7( 6 Votes )

The side BC of Δ ABC is produced to a point D. The bisector of A meets side BC in L, If ABC = 30° and ACD = 115°, then ALC =
A. 85°

B. 72°

C. 145°

D. None of these

Answer :

Given,

ABC = 30o


ACD = 115o


By exterior angle theorem,


ACD = A + B


115o = A + 30o


A = 85o


ACD + ACL = 180o (Linear pair)


ACL = 65o


In


ALC + LAC + ACL = 180o


ALC + A + 65o = 180o


ALC = 72.5o

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