1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 A 19 B 19 C 19 D 19 E 20 A 20 B 20 C 20 D 20 E

West Bengal Mathematics

15. Area and Perimeter of Triangle and Quadrilateral Shaped Region

1. Real Numbers
2. Laws of Indices
3. Graph
4. Co-ordinate Geometry: Distance Formula
5. Linear Simultaneous Equations
6. Properties of Parallelogram
7. Polynomial
8. Factorisation
9. Transversal and Mid-Point Theorem
10. Profit and Loss
11. Statistics
12. Theorems on Area
13. Construction: (Construction of a Parallelogram whose measurement of one angle is given and equal in area of a triangle)
14. Construction: (Construction of a triangle equal in area of a quadrilateral)
15. Area and Perimeter of Triangle and Quadrilateral Shaped Region
16. Circumference of Circle
17. Theorems on concurrence
18. Area of Circular Region
19. Co-ordinate Geometry: Internal and External Division of Straight Line Segment
20. Co-ordinate Geometry: Area of Triangular Region
21. Logarithm

Let us Do 15.1

Let us do yourself 15.2

Let us do 15.3

Let us do the sum 15.1

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 A 19 B 19 C 19 D 19 E 20 A 20 B 20 C 20 D 20 E

Calculate and See 15.2

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 A 21 B 21 C 21 D 21 E 21 F 22 A 22 B 22 C 22 D 22 E

Let us see by calculating 15.3

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 A 17 B 17 C 17 D 17 E 18 A 18 B 18 C 18 D 18 E

Q. 164.6( 13 Votes )

The cost of carpe

Class 9th West Bengal Mathematics 15. Area and Perimeter of Triangle and Quadrilateral Shaped Region

Answer :

Let original length be L and breadth be B.

L = 18m. B = ?

Area = L × B = 18B

New length = 18m, new breadth = B - 4 m

New Area = 18(B - 4)

Let the rate be X per sqm.

Now, 18B × X = 2160

18(B - 4) × X = 1620

Dividing two equations,

1620B = 2160(B - 4)

B = 16m

Perimeter = 2(L + B) = 68m

Area = L × B = 16 × 18m² = 288m²

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