Answer :

Given: Area of circle = 154 cm2

We know that

Area of a circle = πr2

πr2 = 154

r2 = 7× 7

r = 7 cm

Also, Diameter of the circle = 2× radius

CE = 2× 7 = 14 cm

This acts as the diagonal of the inscribed square.

So, the diagonal of the square BCDE= 14 cm

Let the side of the square be x cm

We know that each angle of a square is 90°.

Using Pythagoras theorem,

CD2 +DE2 = CE2

x2+ x2 = 142

2x2 = 196

x2 =98

Side of the square =7√2 cm

We know that Area of a Square = side× side

Area of BCDE =98 cm2

Perimeter of a square = 4× side

Perimeter of BCDE = 4× 7√2 = 28√2 cm

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