# Solve the following equations: , then x is equal to [CBSE 2013] Now we will put Now, we will put x= siny in the given equation, and we get,    1 – siny = cos2y as 1 - cos2y = sin y

2sin2y = sin y

siny(2siny - 1) = 0

siny = 0 or 1/2

x = 0 or 1/2

Now, if we put then we will see that,

L.H.S. =    R.H.S

Hence, is not the solution of the given equation.

Thus, x =

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